> Could be, but would not change the dimensional relationship
> that gravitational attraction at the nuclear level
> is related to universe expansion.
If you take enough constants you'll always find a way to combine
them such that the units match. That's simple combinatorics, not
science.
> I would reverse, the question.
> What nuclear particles in this range would fulfill this mass condition.
> Maybe we should look.
Given the thickness of the PDG booklet I believe you'll find
something close. Tweak the Hubble constant to your favorite value
within its error range and you're done. Still there is no
scientific content, no theory why this combination of constants
is more meaningful than the next one with matching units.
> > Why is the proton radius divided by the Hubble constant almost
> > exactly the speed limit on German country roads?
> >
> that would be Proton radius * Hubble constant
> 8E-15 cm * 2.31E-18 sec^-1 = 1.85E-32 cm/sec
> Too slow for German country roads.
Well, I in fact divided. Then the numbers match but the units
don't. Reading management documents makes me dizzy ...
-- Jo:rg
Richard Saam - 27 Feb 2007 09:53 GMT
>>Could be, but would not change the dimensional relationship
>>that gravitational attraction at the nuclear level
[quoted text clipped - 3 lines]
> them such that the units match. That's simple combinatorics, not
> science.
Its called dimensional analysis.
This is not like combinations of math constants
such as pi, Euler number, natural log, etc.
Yes, science with Perhaps a bit of engineering.
We are not taking any constants, but universal constants with definite
dimensions and observed numerical values.
Any dimensionally correct combination of universal constants results in another
universal constant with comparable integrity
in accordance with least component universal constant significant digit.
For example, take the fine structure constant
that Sir Eddington contemplated: e^2 / h c = 1/137.03599976(50)
It is made of charge(e), Planck (h) and speed of light (c)
and is used with integrity in itself although
composed of three universal constants.
>>I would reverse, the question.
>>What nuclear particles in this range would fulfill this mass condition.
[quoted text clipped - 3 lines]
> something close. Tweak the Hubble constant to your favorite value
> within its error range and you're done.
I have looked and have not found one that fits.
Something is missing which prompted my original question.
Still there is no
> scientific content, no theory why this combination of constants
> is more meaningful than the next one with matching units.
We have disagreement here.
By definition, universal constants were derived
by fitting observed data to theory
'c' relativity theory
'h' quantum theory
'H' Hubble universe expansion theory
'G' Newton's gravity theory
In the equation:
h*H = 2*G*m^2/R
h*H is quantum theory h*nu with nu replaced by H
and
2*G*m^2/R is gravitational energy equation.
Richard