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A Hollow Black Hole?

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Robert Karl Stonjek - 29 Mar 2007 13:05 GMT
Yes, yes, they are dense and have a singularity.  Well, we can't crack one
open and have a look.  But we can observe Neutron stars and if a Black Hole
could be hollow you would expect to find a similar analogy in Neutron Stars.

So here is the process.  We know that just below the Chandrasekhar Limit a
star will form a Neutron Star, above it forms a Black Hole.  Way below the
limit it just explodes in a supernova blast.

But what happens if it begins to explode even though it has a great mass?
And why wouldn't it begin to explode when the star collapses and everything
inside heats up?  So the inside explodes but is stifled by the collapsing
mass.  The momentum of the explosion is conserved in the form of angular
momentum and the heat inside escapes in a huge stream of energy through some
crack in the now super solid neutron shell - our lighthouse beam from which
we can measure its rotational speed.

A neutron star would have to rotate at an enormous speed to prevent further
collapse or the internal pressure would have to be extremely great to hold
the shell from collapsing or there would have to be some combination of the
two.

The reason why this scenario seems at all plausible is the discovery of
extremely rapidly rotating Neutron Stars, well beyond what was thought to be
the speed limit.  See 'Fastest spinning star may have exotic heart'
http://space.newscientist.com/article/dn11221?DCMP=NLC-nletter&nsref=dn11221
(Automatically posted to members of 'Physical Sciences'
http://groups.yahoo.com/group/physical_sciences/ )

The rotational speed of this object is 1,122 rotations per second.  Neutron
Stars typically have a diameter of 10-15 kilometres.  A little arithmetic
tells me that the surface speed is between 32,248 and 52,873 km/s or less
than 1/6 the speed of light - that is one wild ride :)

Surely that speed is sufficient to support a hollow shell even in a neutron
star - or is it?  What speed would be necessary?

There are some wonderful GR minds here at sci.physics.relativity - surely
one of them can model such an object?  Select a mass just below the
Chandrasekhar Limit and a diameter typical of neutron stars of 10~15km.  I
understand the density of the neutron stars are all much the same, so one
only needs to calculate the diameter of a solid neutron star and then
increase the diameter to form a hollow cavity.  Then calculate the required
rotational speed to prevent the hollow cavity from being overwhelmed by the
dense matter of the star.  Is a rotational speed of 1,122 sufficient?  Is
the surface speed less than c?

If a neutron star can do it then a hollow Black Hole can not be ruled out.

Objections on aesthetic or philosophical grounds are of little value here -
the hollow sphere should be modelled first, the required rotational speed
calculated and checked against the highest possible speed for such objects,
and then possible evolutionary paths to the formation of the object can be
explored.  Can anyone rise to this challenge?

Of course if this issue has been considered before then please point us to
it :)

Signature

Kind Regards
Robert Karl Stonjek

George Dishman - 29 Mar 2007 18:04 GMT
> Yes, yes, they are dense and have a singularity.

GR is not a quantum theory so we cannot analyse a black hole
fully. If we ignore that quantum aspect, for an isolated
black hole (which isn't accreting) all the mass is in the
central singularity. That is a point of zero volume hence
infinite density (in reality there might be some quantum
limit to that) and outside that point the density is zero.

> Well, we can't crack one
> open and have a look.  But we can observe Neutron stars and if a Black
> Hole
> could be hollow ...

How can a point be hollow? That doen't even make sense.

> ...  We know that just below the Chandrasekhar Limit a
> star will form a Neutron Star, above it forms a Black Hole.  Way below the
> limit it just explodes in a supernova blast.

No, way below (like our Sun) it turns into a red giant
and then a white dwarf, or even further below it is a
brown dwarf.

> But what happens if it begins to explode even though it has a great mass?
> And why wouldn't it begin to explode when the star collapses and
> everything
> inside heats up?

That's what happens, the star collapses, the outsides are
blown out and in some cases the centre is compressed above
the limit where a black hole forms. The details of supernovae
vary with the type and the best thing you can do is to search
the web for descriptions of the various processes.

> The reason why this scenario seems at all plausible is the discovery of
> extremely rapidly rotating Neutron Stars, well beyond what was thought to
[quoted text clipped - 13 lines]
> neutron
> star - or is it?  What speed would be necessary?

Nothing could support a shell, the material at the poles
is not moving and will collapse. The effect of rotation,
like that of any star, will be to make the shape slightly
oblate.

> There are some wonderful GR minds here at sci.physics.relativity - surely
> one of them can model such an object?  Select a mass just below the
> Chandrasekhar Limit and a diameter typical of neutron stars of 10~15km.  I
> understand the density of the neutron stars are all much the same, so one
> only needs to calculate the diameter of a solid neutron star and then
> increase the diameter to form a hollow cavity.

Try calculating the pressure as a function of depth going
down from the pole to the centre bearing in mind the density
of material.

> If a neutron star can do it then a hollow Black Hole can not be ruled out.
>
> Objections on aesthetic or philosophical grounds are of little value
> here -

Indeed, but the hollow neutron star is ruled out by
hydrostatics and a hollow black hole is ruled out
because a point has no volume.

> Of course if this issue has been considered before then please point us to
> it :)

I doubt anyone has given the idea any thought at all,
what you will find if you look is a lot of work trying
to determine the "equation of state" for neutron stars.

George
Robert Karl Stonjek - 30 Mar 2007 12:43 GMT
> > Yes, yes, they are dense and have a singularity.
>
[quoted text clipped - 11 lines]
>
> How can a point be hollow? That doen't even make sense.

A Schwarzschild Radius can be of any size, including a universe sized
extension - there need not be a point in every case.  A Black hole only
needs to have an escape velocity of c, and a hollow sphere can have
sufficient mass to curve space enough to qualify as a black hole.

The assumption that all Black Holes have a singularity is based on the
extrapolation of their evolution and ignores the possibility of high
rotational speeds.

> > But what happens if it begins to explode even though it has a great mass?
> > And why wouldn't it begin to explode when the star collapses and
[quoted text clipped - 11 lines]
> > be
> > the speed limit.  See 'Fastest spinning star may have exotic heart'

http://space.newscientist.com/article/dn11221?DCMP=NLC-nletter&nsref=dn11221
> > (Automatically posted to members of 'Physical Sciences'
> > http://groups.yahoo.com/group/physical_sciences/ )
[quoted text clipped - 42 lines]
>
> George
Greg Neill - 30 Mar 2007 12:56 GMT
> A Schwarzschild Radius can be of any size, including a universe sized
> extension - there need not be a point in every case.  A Black hole only
> needs to have an escape velocity of c, and a hollow sphere can have
> sufficient mass to curve space enough to qualify as a black hole.

No real material employing the known forces of nature
in its structure can withstand the forces that obtain
from gravitation below an event horizon.  Any material
that is not in a central singularity soon will be (for
suitable values of "soon" that depend upon the overall
size of the black hole).

> The assumption that all Black Holes have a singularity is based on the
> extrapolation of their evolution and ignores the possibility of high
> rotational speeds.

High rotational speeds are not sufficient to hold a shell
of matter from collapsing inside an event horizon.  The
rotational speed of the matter would have to exceed the
speed of light, and it would only help at the equator of
the shell.
Robert Karl Stonjek - 30 Mar 2007 13:42 GMT
> > A Schwarzschild Radius can be of any size, including a universe sized
> > extension - there need not be a point in every case.  A Black hole only
[quoted text clipped - 17 lines]
> speed of light, and it would only help at the equator of
> the shell.

Yes, we've killed off this one - question to freshman, ten minutes to
explain why a black hole can't be hollow...
George Dishman - 30 Mar 2007 14:58 GMT
>> > Yes, yes, they are dense and have a singularity.
>>
[quoted text clipped - 16 lines]
> needs to have an escape velocity of c, and a hollow sphere can have
> sufficient mass to curve space enough to qualify as a black hole.

Let's draw a section of what you seem to be suggesting:

                     |####|
    +              A |####| B
                     |####|

    ^                ^    ^
    |                |    |
    |                |    |
The centre          The shell

Points A and B are just inside and just outside the shell.
The total mass enclosed by a concentric sphere passing
through A is zero so that doen't produce a horizon so I
suppose you are saying the Schwarzschild Radius is the
distance from the centre to point B.

Now as has been said, GR is subtely different from Newtonian
gravity. In the latter, an object fired outwards from the
surface of the shell could move past point B but could not
escape and would fall back. That's not the case in GR. Let
an object fall from some large distance starting nearly at
rest. When it reaches point B heading for the centre, it's
fre-fall speed will reach the speed of light. Between B and
when it hits the shell, the speed exceeds that of light (in
some suitable coordinate system!). If you try to fire
something upwards at point B, it has to be launched at the
speed of light relative to free-falling (inertial) material
just to stay at point B. As you know from SR, you cannot
move faster than the speed of light in any inertial frame,
including that of the free-fall material as it passes you.

The bottom line is that your shell material must move faster
than the speed of light relative to free-fall material if it
is to stay at a constant radius and that as we know is
impossible in GR so the shell collapses.

> The assumption that all Black Holes have a singularity is based on the
> extrapolation of their evolution and ignores the possibility of high
> rotational speeds.

No, it is based on the impossibility of moving faster than
the speed of light. Your shell material will inevitably fall
towards the centre accelerating as it do so and the process
has no end in GR so the ultimate fate is for the entire mass
to be come a mathematical point at the centre. The total
mass remains the same of course and so does the Schwarzschild
Radius so the event horizon is a sphere passing through
point B.

Note that for a supermassive black hole, the acceleration at
the horizon can be less than 1g, and in free fall you don't
even feel that. You could fall towards one of those, pass the
horizon and be as unaware of the event as someone on a ship
passing below the horizon as seen by someone on a cliff some
miles away.

Andrew Hamilton's pages on black holes are excellent:

http://casa.colorado.edu/~ajsh/schw.shtml

Only the distortions he shows would tell you the horizon was
behind you.
George
Jeff Root - 30 Mar 2007 20:39 GMT
> GR is not a quantum theory so we cannot analyse a black
> hole fully. If we ignore that quantum aspect, for an isolated
> black hole (which isn't accreting) all the mass is in the
> central singularity. That is a point of zero volume hence
> infinite density (in reality there might be some quantum
> limit to that) and outside that point the density is zero.

My conception of the interior of a black hole is that the
singularity is a mathematical limit, or extrapolation of what
is actually happening, but is never actually reached.  In my
view, the matter falling into and forming the black hole (both
the original collapsing star and any matter which falls in at
a later time) is forever falling toward the center, becoming
ever more compressed circumferentially but ever more
stretched out (spaghettified!) radially.  The ever-increasing
density of the center part of the black hole causes the
curvature of spacetime there to continually increase, so
that in effect the gravity well is forever getting deeper.  By
some measure (relative to what, I don't know), I think it is
increasing in depth at the speed of light.

Of course, none of this has any implication for what an
observer would see, even if the observer were inside the
black hole relative to another observer farther out.  The
black hole is always just a featureless black hole.  And
in contrast to the original post and the main point of this
thread, I'm ignoring rotation.

 -- Jeff, in Minneapolis
Ahmed Ouahi, Architect - 30 Mar 2007 21:13 GMT
The usual approach of science of constructing a mathematical model cannot
answer the questions of why there should be a universe for the model to
describe.

Why does the universe go to all the bother of existing?

-- Stephen Hawking

--
Ahmed Ouahi, Architect
Best Regards!

> > GR is not a quantum theory so we cannot analyse a black
> > hole fully. If we ignore that quantum aspect, for an isolated
[quoted text clipped - 25 lines]
>
>   -- Jeff, in Minneapolis
Tom Roberts - 31 Mar 2007 05:48 GMT
> A Schwarzschild Radius can be of any size, including a universe sized
> extension - there need not be a point in every case.

Hmmm. In the Schwarzschild manifold of GR, the horizon is nowhere near
the entire universe -- the horizon is of finite "radius" while the
universe of that particular manifold is spatially infinite.

Now some people, yourself included, seem to think it is possible for a
"Schwarzschild black hole" to inhabit our universe. Strictly speaking
this simply is not possible, as the universe we inhabit is quite clearly
not well modeled by the Schw. manifold (e.g. that manifold contains no
stars, planets, or people).

However it does seem likely that objects similar in exterior appearance
to a Schw. black hole could inhabit our universe, though it is extremely
unlikely -- Kerr, Neumann, and/or Reisner-Nordstrom black holes are
vastly more likely (they have nonzero angular momentum and/or charge).

> A Black hole only
> needs to have an escape velocity of c,

No. A black hole only needs a trapped surface. You are thinking in
Newtonian mechanics (NM), not GR -- "escape velocity" does not really
apply to black holes. The difference is:

 NM: a freefalling object traveling with less than the escape
     velocity can still travel outward, but must fall back;
     a rocket can escape with any velocity > 0 as long as it
     can accelerate sufficiently (including moving slower than
     escape velocity).

 GR: no object or light ray can travel outward from an event
     horizon, regardless of how strongly it can accelerate.

A trapped surface is the local definition of an event horizon; it is a
surface from which all light rays travel to only one side of the surface
(i.e. none travel "outward"). This is MUCH more powerful than the escape
velocity of NM.

> and a hollow sphere can have
> sufficient mass to curve space enough to qualify as a black hole.

Yes, one can imagine a _collapsing_ hollow sphere that is massive enough
to have a trapped surface outside. An observer inside would be unaware
of the presence of the horizon or the inevitability of it collapsing in
and crushing her (because there is a series of trapped surfaces
traveling inward with local speed c so no warning could possibly reach
her before they do).

    At least I'm pretty sure that is how the geometry of a
    collapsing spherical shell would work out; I do not know
    of any actual solution describing this.

> The assumption that all Black Holes have a singularity is based on the
> extrapolation of their evolution and ignores the possibility of high
> rotational speeds.

Hmmm. This is more a definition of what "black hole" means than any
assumption. That is, all black hole manifolds in GR have some sort of
singularity -- the presence of an event horizon is the defining
characteristic of a black hole, and one of the singularity theorems
states that the presence of a trapped surface (aka horizon) implies the
presence of a singularity (loosely; there are additional caveats). Note,
however, this is "presence" in the 4-d manifold, and for the case of a
collapsing system there could be no singularity inside until the
collapse is nearly complete -- that is, do not confuse "time in the
manifold" with "time to an external analyst".

Jeff Root said:
> In my
> view, the matter falling into and forming the black hole (both
> the original collapsing star and any matter which falls in at
> a later time) is forever falling toward the center, becoming
> ever more compressed circumferentially but ever more
> stretched out (spaghettified!) radially.

This is NOT what happens in GR. In GR any timelike trajectory inside the
event horizon of a Schw. black hole intersects the singularity at the
center in finite proper time.

Tom Roberts
Jeff Root - 31 Mar 2007 06:49 GMT
Tom Roberts replied to Jeff Root:

> > In my view, the matter falling into and forming the black
> > hole (both the original collapsing star and any matter which
[quoted text clipped - 5 lines]
> inside the event horizon of a Schw. black hole intersects the
> singularity at the center in finite proper time.

Can you show what the proper time would be for some simple
case of a neutral particle free-falling straight in to a nonrotating
stellar-mass black hole?

Since I know that everything which falls into a black hole *is*
stretched in the radial direction, can you also give a measure
of that stretching for the test particle?  Is it stretched only in
a space dimension, or only in time, or both, or what?

 -- Jeff, in Minneapolis
Ahmed Ouahi, Architect - 31 Mar 2007 09:26 GMT
All political thinking for years past has been vitiated in the same way.

People can foresee the future only when it coincides with their own wishes,
and the most grossly obvious facts can be ignored when they are unwelcome.

-- George Orwell

--
Ahmed Ouahi, Architect
Best Regards!

> Tom Roberts replied to Jeff Root:
>
[quoted text clipped - 18 lines]
>
>   -- Jeff, in Minneapolis
Robert Karl Stonjek - 31 Mar 2007 08:36 GMT
> > A Schwarzschild Radius can be of any size, including a universe sized
> > extension - there need not be a point in every case.

Toom Roberts Said:
> Hmmm. In the Schwarzschild manifold of GR, the horizon is nowhere near
> the entire universe -- the horizon is of finite "radius" while the
[quoted text clipped - 5 lines]
> not well modeled by the Schw. manifold (e.g. that manifold contains no
> stars, planets, or people).

No, Tom, I don't think there is any chance that our universe could be a
Schwarzschild black hole but I do consider a 'universe sized Schwarzschild
black hole' which is quite different.  Further, I am considering only the
matter and not the space.

It seems rather obvious that if our universe was something like a
Schwarzschild black hole then it would necessarily be in the process of
collapsing to that singularity you mention, though this could take many
billions of years to happen.  Even so, such a collapse would blueshift the
light from distant stars and galaxies - indeed, it would be quite *opposite*
to what we observe.  That rules out such a structure from even a
philosophical account of the universe.

In short, the universe can not be both expanding and anything like a
Schwarzschild black hole.

The rotating shell died because of what should have been dead obvious to me
in the first place - rotation does not prevent collapse at the poles...

Signature

Kind Regards
Robert Karl Stonjek

Robert Karl Stonjek - 31 Mar 2007 08:37 GMT
> > > A Schwarzschild Radius can be of any size, including a universe sized
> > > extension - there need not be a point in every case.
> >
> Toom Roberts Said:

The above was a typo - not making fun of anyone - sorry TOM.

Signature

Kind Regards
Robert Karl Stonjek

Greg Neill - 29 Mar 2007 19:15 GMT
> Yes, yes, they are dense and have a singularity.  Well, we can't crack one
> open and have a look.  But we can observe Neutron stars and if a Black Hole
[quoted text clipped - 11 lines]
> crack in the now super solid neutron shell - our lighthouse beam from which
> we can measure its rotational speed.

Explosive momentum is essentially radial, thus linear.
Angular and linear momenta are conserved separately.
There's no mechanism for converting one to the other.

> A neutron star would have to rotate at an enormous speed to prevent further
> collapse or the internal pressure would have to be extremely great to hold
[quoted text clipped - 15 lines]
> Surely that speed is sufficient to support a hollow shell even in a neutron
> star - or is it?  What speed would be necessary?

A neutron star has not collapsed beyond forcing the electrons
to combine with the protons.  Neutron degeneracy pressure can
resist further callapse up to some critical mass.  Now,
rapid rotation can certainly help by providing a centrifugal
effect.  This is equivalent to reducing the mass-energy
density of the object.  Ultimately, the ability of a shell to
resist collapse depends upon the compressive strength of the
material along with whatever forces are aiding it.

Perhaps you are thinking that, if the outer shell were
rotating and the interior material was not, then the
shell could resist ultimate collapse while the interior
headed towards black holedom.  A couple of problems
arise.  First, the shell would be outside of the event
horizon (the mass-energy density is lowered by the
rotation of the shell).  Second, the poles of the
shell would not benefit from the rotation.  The matter
at the poles would end up collapsing.

> There are some wonderful GR minds here at sci.physics.relativity - surely
> one of them can model such an object?  Select a mass just below the
[quoted text clipped - 5 lines]
> dense matter of the star.  Is a rotational speed of 1,122 sufficient?  Is
> the surface speed less than c?

If you increase the diameter of the object while maintaining
the same amount of matter, the density will drop and you'll
no longer be close to the Chandrasekhar limit.

> If a neutron star can do it then a hollow Black Hole can not be ruled out.

I take it that you're thinking of a rotating shell of matter
(neutronium) spinning just below an event horizon and
resisting collapse.  As I pointed out above, the poles
of the shell would be a problem -- the neutron degeneracy
pressure would be insufficient to prevent them from
collapsing and whole shell would be consumed.

> Objections on aesthetic or philosophical grounds are of little value here -
> the hollow sphere should be modelled first, the required rotational speed
[quoted text clipped - 4 lines]
> Of course if this issue has been considered before then please point us to
> it :)
Robert Karl Stonjek - 30 Mar 2007 12:49 GMT
> > Yes, yes, they are dense and have a singularity.  Well, we can't crack one
> > open and have a look.  But we can observe Neutron stars and if a Black Hole
[quoted text clipped - 24 lines]
> > extremely rapidly rotating Neutron Stars, well beyond what was thought to be
> > the speed limit.  See 'Fastest spinning star may have exotic heart'

http://space.newscientist.com/article/dn11221?DCMP=NLC-nletter&nsref=dn11221
> > (Automatically posted to members of 'Physical Sciences'
> > http://groups.yahoo.com/group/physical_sciences/ )
[quoted text clipped - 48 lines]
> pressure would be insufficient to prevent them from
> collapsing and whole shell would be consumed.

Ahh, the poles.
Well, if ever a neutron donut is discovered, I thought of it first :)

Signature

Kind Regards
Robert Karl Stonjek

 
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