Wiki et al show tables of the first 20 or 50 starsnearest the earth.
The distances for the first few are
.. .. .. 4.3 6.0 7.7 8.4 8.6 9.4 10.4 LY
1.7 1.7 .7 .2 1.2 1 the differences
Why are there no stars from 0 to 4.3 LY? From the difference list
there should be at least 2 closer than 4.3.
These are probably the few that can be measured using the parallactic
effect. It just doesn't seem likely that such a void exists.
John Polasek
Richard Tobin - 20 Jul 2008 22:32 GMT
>The distances for the first few are
>.. .. .. 4.3 6.0 7.7 8.4 8.6 9.4 10.4 LY
> 1.7 1.7 .7 .2 1.2 1 the differences
>Why are there no stars from 0 to 4.3 LY? From the difference list
>there should be at least 2 closer than 4.3.
There's no "should" about it. You can't deduce anything from such a
small set of data.
But even supposing they were uniformly distributed, the volume with 10
LY of earth is 8 times the volume within 5. The differences in
distances would be expected to tend to zero.
-- Richard

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Androcles - 20 Jul 2008 22:41 GMT
| Wiki et al show tables of the first 20 or 50 starsnearest the earth.
| The distances for the first few are
[quoted text clipped - 5 lines]
| effect. It just doesn't seem likely that such a void exists.
| John Polasek
Why are you a cretin? There should be at least 55 morons
writing to sci.astro ahead of you and you the closest. The next
poster is at least an hour away from you, it just doesn't seem
likely that such a void exists.
Look, imbecile, that's the way it IS, there is no "why" to it.
Landy - 21 Jul 2008 11:15 GMT
> | Wiki et al show tables of the first 20 or 50 starsnearest the earth.
> | The distances for the first few are
[quoted text clipped - 11 lines]
> likely that such a void exists.
> Look, imbecile, that's the way it IS, there is no "why" to it.
And why are you such an arsehole?
The poster was simply asking an innocent question.
If you can't be constructive, why don't you just shut the f.ck up?
Peter Webb - 25 Jul 2008 13:39 GMT
> | Wiki et al show tables of the first 20 or 50 starsnearest the earth.
> | The distances for the first few are
[quoted text clipped - 11 lines]
> likely that such a void exists.
> Look, imbecile, that's the way it IS, there is no "why" to it.
But there is a simple "why" to it.
The number of stars of stars less than x light year ways away is
proportional to x^3, and the number between x and x+1 light years away is
proportional to 3x^2. So the number close to the earth falls away with the
square of the distance; its not a linear relationship; and the difference is
most dramatic for small distances (x =1, 2, 3).
Look, imbecile, that is the way it IS, the "why" is a geometrical argument.
Androcles - 25 Jul 2008 15:46 GMT
| > | Wiki et al show tables of the first 20 or 50 starsnearest the earth.
| > | The distances for the first few are
[quoted text clipped - 21 lines]
|
| Look, imbecile, that is the way it IS, the "why" is a geometrical argument.
Look, moron:
http://antwrp.gsfc.nasa.gov/apod/ap030323.html
There is just one star within one AU of the EARTH (your chosen
reference point), and four within 5 light years, namely Sol, Proxima
Centauri, Alpha Centauri A and Alpha Centauri B.
Then of course there is Barnard's star, moving rapidly.
http://www.solstation.com/stars/barnards.htm
At 8 light years you can add Sirius A and Sirius B.
How many pips in an orange and why are they not at the rind?
Because they are not homogeneous.
What "geometrical argument", sh.t-for-brains?
Craig Markwardt - 20 Jul 2008 23:12 GMT
> Wiki et al show tables of the first 20 or 50 starsnearest the earth.
> The distances for the first few are
[quoted text clipped - 4 lines]
> These are probably the few that can be measured using the parallactic
> effect. It just doesn't seem likely that such a void exists.
If there are 7 stars within a radius of 10 light-years, then the
density is .00168 stars per cubic light year. Assuming a uniform
density (no voids), the cumulative number should grow as R^3.
On average, the first star will appear at a radius between 4-6 light
years, which is a reflection that the inner 5 light years contains
only about 1/8th of the total volume out to 10 light years. On
average, the next stars will be separated by 1.8, 1.1, 0.8, 0.7, 0.6,
0.5 light years respectively. Seems like a reasonable approximation
of reality to me.
CM
John C. Polasek - 21 Jul 2008 02:21 GMT
>> Wiki et al show tables of the first 20 or 50 starsnearest the earth.
>> The distances for the first few are
[quoted text clipped - 17 lines]
>
>CM
I see. I agree, after a rough start, the sequence smooths out. Easier
if you use 7stars/10^3 or .007 (in place of .00168 ) 'really really
cubic' light years, bypassing the 4/3pi.
Mystery solved.
John Polasek
Mike Dworetsky - 21 Jul 2008 13:04 GMT
> Wiki et al show tables of the first 20 or 50 starsnearest the earth.
> The distances for the first few are
[quoted text clipped - 5 lines]
> effect. It just doesn't seem likely that such a void exists.
> John Polasek
If you actually do the arithmetic on star density in our Galaxy, 4 LY is
just about the diameter of a sphere containing one solar mass. So there is
no mystery about why the nearest star is 4.3 LY away.
Very roughly:
galaxy disk diameter 100,000 LY
disk thickness 1,000 LY
Disk volume pi R^2 x T = 3.14 (50,000)^2 x 1000 ~ 10^13 cubic LY (roughly)
Mass of the galactic disk is of order 10^11 solar masses (possibly less, as
the halo seems to have most of the mass).
Volume per solar mass ~100 cubic LY. Cube root of 100 CLY is 4.64 LY which
is average edge of a "box" with one solar mass inside. If stars were evenly
spaced they would therefore be about 4-5 LY apart. In fact, the average
star is smaller than the Sun but even this would not change the result by
more than a factor of 2.
So it is not surprising that the nearest star is currently about 4 LY away.
Space is big.

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John C. Polasek - 21 Jul 2008 16:22 GMT
>> Wiki et al show tables of the first 20 or 50 starsnearest the earth.
>> The distances for the first few are
[quoted text clipped - 28 lines]
>So it is not surprising that the nearest star is currently about 4 LY away.
>Space is big.
Your 1 solar mass/100CLY or 5.6e-21 kg/mmm is about 3.7e5 times the
density 1.5e-26 of the universe, m/l.
Thank you.
John Polasek